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x^2+34x-2520=0
a = 1; b = 34; c = -2520;
Δ = b2-4ac
Δ = 342-4·1·(-2520)
Δ = 11236
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{11236}=106$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(34)-106}{2*1}=\frac{-140}{2} =-70 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(34)+106}{2*1}=\frac{72}{2} =36 $
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